# Acceleration in an Electron Gun

acceleration zone
The acceleration voltage generates an electric field:$$E=\frac{V_{\text a}}{\text d}$$In the electric field the electrons experience a force F:$$F_{\text{el}}=E\cdot e = \frac{V_{\text a}\cdot e}{\text d}$$So beetween cathode and anode work is done:$$W_{\text{el}}=F_{\text{el}}\cdot \text {d} = \frac{V_{\text a}\cdot e\cdot \text d}{\text d}= V_{\text a}\cdot e$$This work raises the kinetic energy of the electron.
The kinetic energy Ekin of an electron is:$$E_{\text {kin}}= \frac {1}{2}mv^2$$Equal this with the work done:$$\frac {1}{2}mv^2=e \cdot V_{\text a}$$So there is the final speed:$$\bbox[5px,border:2px solid red] {v_{\text{end}}=\sqrt{2\cdot \frac{e}{m}\cdot V_{\text a}}}$$