It holds that:
$$\frac{B_x}{\mu_0}=M_x+H_x$$
and along the axis of symmetry of the magnet:
$$ { \frac{B_x(x)}{\mu_0} = \frac{1}{2} M_x \left( \frac{\frac{L}{2}-x}{\sqrt{\left(\frac{L}{2} - x\right)^2 + R^2}} + \frac{\frac{L}{2} + x}{\sqrt{\left(\frac{L}{2} + x\right)^2 + R^2}} \right)} \\$$
Task: Use measurements and the slider to determine the magnetic field!
\(M_x=\)\(\frac{\mathrm{kA}}{\mathrm{m}}\)
Derivation of the formula
\(\mu_0 = 1,2566 \cdot 10^{-6} \frac{\mathrm{N}}{\mathrm{A^2}} ,\\ R=7,5\mathrm{mm}, \\L=100\mathrm{mm}\)